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Calculating confidence intervals.

SCENARIO: The U.S. Bureau of Labor Statistics (http://www.bls.gov) released hourly wage figures for western countries in 2000 in the manufacturing sector. The hourly wage was $24.01 in Germany, $22.00 in Japan, and $19.86 in the United States. Problem: Construct a 95% confidence intervals for the average hourly wage rates in Germany and the United States. Compare the results. Note: Assume that in all three countries, the standard deviation of hourly labor rates is $3.

Subject:

Statistics

Topic:

All Topics

Posting ID:

3932

OTA ID:

102454

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Binomial Distribution

The manager of a restaurant claims that only 3% of the customers are dissatisfied with the service. If this claim is true, what is the probability that the number of dissatisfied customers, in a random sample of 25 customers will be a) 0 b) at least 1 c) between 1 and 5 inclusive d) greater than 5 e) 25

Subject:

Statistics

Topic:

All Topics

Posting ID:

3933

OTA ID:

102799

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3 Probability Questions

Here are questions 33 and 34 to assist in answering question 52. 33) Let X be a random variable with probability density f(x)={c(1-x^2), -1click for more

Subject:

Statistics

Topic:

All Topics

Posting ID:

3973

OTA ID:

101298

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Probability Questions

30)Let X be a Poisson random variable with parameter (lambda). Show that P {X=i} increases monotonically and then decreases monotonically as i increases, reaching its maximum when i is the largest integer not exceeding (lambda). Hint: Consider P{X=i}/P{X=i-1}. 37) Let X1, X2, ...., Xn be independent random variables, each having a uniform distribution function of M, Fm (.), is given by Fm(x)=x^n, 0(less than or equal to)x(less than or equal to) 1 What is the probability density function of M? 40) Suppose that two teams are playing a series of games, each of which i s independently won by team A with probability p and by team B with probability 1-p. The winner of the series is ... click for more

Subject:

Statistics

Topic:

All Topics

Posting ID:

3974

OTA ID:

103059

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Conditional probability

4) In a survey conducted to determine cost of vacations, 164 individuals were randomly sampled. Each person was asked to assess the total cost of his or her most recent vacation. The average cost was $1,386. Assuming that the standard deviation was $400, find a 94% confidence interval for the average cost of all vacation trips. ANSWER- 1327.28,1444.72 5) Students in a stats class were polled by a surveyor attempting to establish a relationship between hours of study in the week immediately before a major exam and the marks received on the exam. Hours of Study 25, 12, 18, 26, 19, 20, 23, 15, 22, 8 Exam Grades 93, 57, 55, 90,82,95,95,80,85,61 Sum of X=188, Sum of Y=793 Xsquared... click for more

Subject:

Statistics

Topic:

All Topics

Posting ID:

3979

OTA ID:

103058

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