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Calculating the sample size given confidence levels and standard deviation.

A researcher is interested in estimating the average salary of police officers in a large city. She wants to be 95% confident that her estimate is correct. If the standard deviation is $1050, how large a sample is needed to get the desired information and to be accurate within $200?

Subject:

Statistics

Topic:

All Topics

Posting ID:

3842

OTA ID:

101733

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Setting up constraints.

How do I set up the contraints? A firm is engaged in the production of three types of products A, B, and C. The products earn profit of $3, $5 and $4 per unit respectively. Each product goes through three operations: cutting, sewing, and inspection. During the next period, the firm has 300 hours of cutting, 300 hours of sewing, and 150 hours of inspection time available. The sales force requires that at least 1000 units of product 1 be produced next period. The time (in minutes) taken for each product in each department is shown below. (Hint: 4 constraints). -------------- A--------- B----------- C Cutting----- 12 -------- 10 -------- 8 Se... click for more

Subject:

Statistics

Topic:

All Topics

Posting ID:

3928

OTA ID:

101298

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Setting up constraints for profit maximization.

A florist is planning to make up floral arrangements for the upcoming holiday weekend. He has following supply of flowers in stock this Friday and he cannot get any more. Type------Number available------Cost per flower Roses----------800-----------------------0.20 Carnations---4000----------------------0.15 Gardenias-----450-----------------------0.25 The florist can either make an economy arrangement selling for $5.95 or a deluxe arrangement selling for $14.95. Each economy arrangement contains 3 roses, 2 gardenias, and 10 carnations. Each deluxe arrangement contains 6 roses, 3 gardenias and 15 carnations. All unused flowers are sold at $0.10 each to a street vendor. Assu... click for more

Subject:

Statistics

Topic:

All Topics

Posting ID:

3929

OTA ID:

101298

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Statistical Inference

SCENARIO: The U.S. Bureau of Labor Statistics (http://www.bls.gov) released hourly wage figures for western countries in 2000 in the manufacturing sector. The hourly wage was $24.01 in Germany, $22.00 in Japan, and $19.86 in the United States. PROBLEM: Suppose 40 manufacturing workers are selected randomly from across Germany and asked what their hourly wage is. What is the probability that the sample average will be between $23.50 and $24.50? ANSWER: $23.50+24.50=50/40 =$24.11 SECOND PART OFTHE PROBLEM: Suppose 35 manufacturing workers selected randomly from across Japan. What is the probability that the sample average will exceed $23? 19.86/35=0.5 Assu... click for more

Subject:

Statistics

Topic:

All Topics

Posting ID:

3930

OTA ID:

102799

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Calculating the probability in a given situation using the probability distribution table.

The U.S. Bureau of Labor Statistics (http://www.bls.gov) released hourly wage figures for western countries in 2000 in the manufacturing sector. The hourly wage was $24.01 in Germany, $22.00 in Japan, and $19.86 in the United States. PROBLEM: Suppose 50 manufacturing workers are selected randomly from across the United States. What is the probability that the sample average will be less than $18.50? NOTE: Assume that in all three countries, the standard deviation of hourly labor rates is $3.

Subject:

Statistics

Topic:

All Topics

Posting ID:

3931

OTA ID:

102454

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