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· 1-5 · 6-10 · 11-15 · 16-20 · 21-25 · 26-30 · 31-35 · 36-40 · 41-45 · 46-50 · 51-55 ·A retail grocer has decided to market organic "health foods" and will purchase a new line of products from each of two suppliers. Unknown to the grocer, the two suppliers are in financial distress. Past experience has shown that, for firms with similar credit histories, the probability that bankruptcy proceedings will be initiated within one year is .7. We are interested in observing the financial progress of the two suppliers over the next year. For this experiment, the simple events and their associated probabilities are as follows (B1: Supplier 1 declares bankruptcy; N1: Supplier 1 does not declare bankruptcy, etc.): Simple Events are (B1, B2), (B1, N2), (N1, B2), (N1, N2) with assoc... click for more
Subject:
Psychology
Topic:
Psychological Statistics
Posting ID:
10877
OTA ID:
102789
Explains how to compare two population variances using the F table of critical values
Obtain the critical values of the F distribution for the following situations: (a). F .01, numerator df = 8, denominator df = 6 (b). F .01, numerator df = 5, denominator df = 120 (c). F .05, numerator df = 12, denominator df = 24
Subject:
Psychology
Topic:
Psychological Statistics
Posting ID:
10954
OTA ID:
102789
Assigning Probabilities to simple events
When assigning probabilities of two simple events, can we assume that each event is always equally likely to occur and, thus assign .5 to each event? Could you provide an example in your explanation?
Subject:
Psychology
Topic:
Psychological Statistics
Posting ID:
10961
OTA ID:
102789
Calculating probabilities of events
1. What are the steps I need to calculate probability of events occurring? 2. Could you apply these steps to the following example: A fair die is tossed, and the up face is observed. If the face is even, you win $5. Otherwise, you lose $5? What is the probability?
Subject:
Psychology
Topic:
Psychological Statistics
Posting ID:
10963
OTA ID:
102789
Our psychology department received a new statistics text for review. Prof. Smart in his review provided an interesting table of corrections. TYPE: Alterations-20%, Spelling-50%, Spelling and alterations-10% Assuming that spelling and alterations are the only possible types of corrections, calculate the probablility of spotting a correction due to an alteration error or a spelling error AND the probability of detecting no correction. My Answers: Probability of Alteration Error Only: 10% (20%-10%) Probability of Spelling Error Only:40% (50%-10%) Probability of No Correction: 40% (100%)-(40%+10%+10%) Is this right??????
Subject:
Psychology
Topic:
Psychological Statistics
Posting ID:
11131
OTA ID:
103477
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