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Two ships on the surface receive a signal from the bottom at different times. Find the depth of the sea.

Two research ships are distance S= 3600 meters apart on the ocean surface. Ship A now drops an explosive device overboard which sinks and explodes upon reaching the bottom. The sound of the explosion is received by A, directly above, 1.5 seconds before it is received by B. Assume the sound travels at v= 1450 m/sec in sea water. SEE ATTACHMENT #1 for a diagram of the situation. Find D, the depth of the ocean under ship A.

Subject:

Physics

Topic:

Classical Mechanics

Posting ID:

7412

OTA ID:

102950

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Sound frequency and/or wavelength changes due to motion of the observer, and/or the source is the 'Doppler effect'.

A truck is moving at 50 m/sec while its horn emits a steady note at 280 cy/sec. A woman is stationary, 150 meters ahead of the truck. A man is in a car, 200 meters ahead of the truck, moving toward the truck at a speed of 30 m/sec. The speed of the sound is 345 m/sec. PART a. Find the frequency heard by the woman. PART b. Find the frequency heard by the man in the car. PART c. Find the wavelength of the sound ahead of the moving truck. PART d. Find the period of the sound heard by the man.

Subject:

Physics

Topic:

Classical Mechanics

Posting ID:

7414

OTA ID:

102950

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Submarine A detects sound from sub B. Given the frequency received and knowing that emitted, find the velocity of sub B.

Submarine A, with velocity 21 m/sec, receives from directly behind it, the sound with frequency 266 cy/sec, from submarine B which is known to emit sound at 265 cy/sec. The two submarines are 1800 meters apart. Speed of sound in sea water 1450 m/sec. If the two subs maintain courses and speeds, will there be a collision, and if so, in how many seconds?

Subject:

Physics

Topic:

Classical Mechanics

Posting ID:

7435

OTA ID:

102950

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John and Sue are descending on ropes into a cave. Sue's rope breaks and she falls screaming past John. Apply doppler effect.

John, hanging stationary on a rope in an underground cave, hears Sue screaming with frequency f as she falls past him with constant terminal speed S= 53 m/sec. While she is above him he receives her scream as frequency fA, and after she passes him he receives frequency fB, which is 96 cy/sec less than fA. Exactly t= 3.6 seconds after she passes him he hears the sound of her arrival as she splashes into a pool. The velocity of sound is 345 m/sec. PART a. Find the frequency f, of her scream. PART b. How far below John is the pool?

Subject:

Physics

Topic:

Classical Mechanics

Posting ID:

7436

OTA ID:

102950

View Details $1.99 Download Add to Cart

Given two guitar strings' lengths and relative densities, find information about their frequencies and tensions.

The thinnest string on a certain guitar has a linear density one fifteenth the linear density of the thickest string. Both strings are the same length, L= .64 m. NOTE: On a musical scale a note one octave higher than a certain note is twice the frequency of that note. PART a. If both strings have the same tension force, find the ratio of their two fundamental frequencies, 'fhi / flo'. PART b. The fundamental note (first harmonic) of the thicker string is135 cy/sec, and its linear density is .006 kg/m. Find the tension in this string. PART c. Find the frequency and the tension in the thinner string if it is to produce a note which is 3 octaves above the fundamental note of the thicke... click for more

Subject:

Physics

Topic:

Classical Mechanics

Posting ID:

7464

OTA ID:

102950

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