Quantify the effect of direct and shear forces...

Question 2: ... calculate the direct stress in each part of the component ... Question 3: ... if the pin diameter is 30mm find the shear stress developed in the pin ... Please see attachment for complete questions and diagram

Quantify the effect of direct and shear forces ...

Question 4: (a) Calculate the force required to punch out a rectangular hole ... (b) If the maximum force which can be exerted by the press is 45kN, what is the greatest thickness ... Question 5: ... find the factor of safety for the bolts if the coupling transmits a torque of ... (Please see attachment for complete questions. Thanks!)

Analyse planner equilibrium problems

require worked solution for self check purposes Question 3: The built-in beam in Figure Q.3 below has a weight of 30kN and is acted on by veritcal forces of 8kN and 10kN respectively positioned at 3m and 7m for the free end... Please see attached.

Analyses planner equilibrium problems

require worked solution for self check purposes Question 4. The beam shown in Figure Q.4 below is simply supported at points A and C... Select convenient scales and construct the Shear Force and Bending Moment diagrams for the simply supported beam on the accompanying worksheet and determine the following: a) the magnitude and location of the maximum shear force b) the magnitude and location of the maximum bending moment. Please see attached.

Spring mass change

A spring in the vertical position, when carrying a 30-kg load, is stretched to a length of 0.15m. When carrying 50 kg, its length is 0.2m. Determin the work required to stretch the spring from a total length of 0.1m to 0.25m. I know that U=1/2kx, F=kx, k=F/x. Using k=F/x the k1=(30kg*9.81m/s^s)/.15m = 1962kN/m k2=(50kg*9.81m/s^s)/.2m = 2452.5kN/m This confuses me that k (spring constant) can change. Does that mean I use a ratio to find the work of going from 0.1m to 0.25m.