Dynamics Problem

An object turns about a center with constant tangential speed of 5.425m/s. The object is attached to the center by means of a cord of length 2m, and of negligable weight. Determine the values of radius of rotation "R" and "h". (See attachment for full question)

Dynamics Problem

At the instant that an object travels horizontally with a velocity of "v", passes at an elevation of "h" above a second object, the second object is released at an angle "x" to the horizontal with a velocity... (PLEASE SEE ATTACHMENT FOR COMPLETE PROBLEM AND DIAGRAM)

Calculus Based Dynamics (Given Instantaneous Radius of Curvature for Plane Curve is ... Find ... )

An object travels with a constant speed "v" in the x-y plane over a feature that is described by the equation {see attachment}. Given that the instantaneous radius of curvature for any plane curve is: {see attachment}, find the minimum value of "v" that makes the object "weightless" at the apex. Take "g" to equal 9.81 m/s[squared] Neglect object size. *Please see attachment for functions and diagram

Calculus Based Dynamics (Object Collision - Determine Points of Impact and Time of Impact)

Objects 1 and 2 are fired horizontally from the same elevation directly towards each other. Object 1 is fired with velocity {see attachment} while Object 2 is fired with velocity {see attachment}. Initial separation is 3m. Take "g" = 9.81 m/s[squared] - Determine the "x" value of the point of impact - Determine the time "ti" to impact - Determine the "y" value of the point of impact Neglect object size **Please see attachment for velocities and diagram

Assignment Question 3 in Applied Mechanics

Fig. Q3 shows a rigid light beam which is hinged at O to a wall. The beam carries a point mass of m at the free end. The beam is connected at its mid-point to a spring (stiffness k) which is also connected to a support that moves with a vertical motion y = Y sinwt. A damper (coefficient c) connects the mid-point of the beam to a fixed support. (i) By taking moments about O of the forces acting on the beam show that an equation of motion can be obtained with the form 4mx + cx + kx = kY sin ωt Please note that in the equation above the first x should have two dots above it and the second x should have one dot above it only. The reason why they... click for more