DC analysis of transistor circuits

The current gain of the transistor is Beta=75. Determine Vo for [i] Vbb=0, [ii]Vbb=1V, and [iii] Vbb=2V. I'm confused on how to incorporate the load resistance in the KVL calculations. Thank you.

multi-stage transistor circuit analysis

For each transistor, Beta=120 and the B-E turn on voltage is .7V. Find the quiescent base, collector, and emittter current in Q1 and Q2. Also, determine Vceq1 and Vceq2. For the first stage, in the dc analysis I ignored the coupling capacitor and did a Thevenin equivalent resistance/voltage. I did KVL around the BE loop and got ib=14.8 microAmps. ic and ie=2ma. However, when I feed the ic current into the base of the second transistor, I get an astronomically high voltage across the CE loop. Where did I go wrong?

Theveninization of a transisor circuit

Find Icq and Vceq for the circuit when Beta=100. I put the 60k and 30 k resisters in parallel and then did a thevenin equivalence on the parallel combination resistance and the 20k ohm resistor. Then, I did kvl around the b-e loop and got icq=.021ma and vce=.39v. Did I do the thevinin equivalence correctly?

bias stable transisor design problem

The DC load line and Q point of the circuit are shown next to the circuit. For the transistor, Beta=120. Find Re, R1, and R2 such that the circuit is bias stable. Is it valid for me to do a KVL around the C-E loop using ic=4.8ma and vce=6v (ie=ic (b+1/b)) to find RE? And then get Rth=.1(1+beta)*Re? I know I can just arbitrarily choose an r1 and use rth to get r2? How do find the correct values of r1 and r2, and is my approach correct to this point? Thank you.

bias stable circuit design with capacitors

For the circuit, design a bias stable circuit such that Icq=.8mA and Vceq=5V. Let Bf=100. Using the results, determine the percentage change in Icq if Bf is in the range of 75<=Bf<=150. Repeat this if Re=1kOhms. Rth=.1(1+b)re=.1*101*.5Kohms=5050 Ohms I can do KVL around the b-e loop to find Vth, but how do I split the two resisters out of Rth? Anything could be r1*r2/(r1+r2) The capacitors are confusing me. If they act as opens, then RL is irrelevant? By the way, what is the function of the emitter capacitor? (just curious) Is the part B, do you think the author means the difference between the upper value of Icb and the lower value of Icb? Or what percent of icblower is i... click for more