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· 1-5 · 6-10 · 11-15 · 16-20 · 21-25 · 26-30 · 31-35 · 36-40 · 41-45 · 46-50 · 51-55 ·a complete circuit contains two parallel -connected diveices
the resistance of the first device is 12 ohms, the resistance of the second divice is 4 ohms, and the voltage developed by the generator is 40 V. what is the magnitude of the current flowing through the first device? (a) 3033 A (b) 8A (c)10A or (d) 13.32A ?
Subject:
Electrical and Computer Engineering
Topic:
Electrical and Electronic Circuits
Posting ID:
13266
OTA ID:
102509
a circuit contains two devices that are connected tin parallel
a circuit contains two devices that are connected in parallel. if the resisstances of one of these devices is 12ohms and the resistance of the other divice is 4ohms, the total resistance of the two devices is? (a) 0.0625 (b) 0.333 ohms (c) 3 ohms (D) 16 ohms ?
Subject:
Electrical and Computer Engineering
Topic:
Electrical and Electronic Circuits
Posting ID:
13281
OTA ID:
103642
Complimentary output rectifier voltage output wave-forms
In the complementary output rectifier, If Vs=26*sin 2*pi*60*t Volts, sketch the output waveforms vo+ and vo- versus time, assuming Vgamma=.6V for each diode. I don't understand the graphic questions. Will there ever be a time when the voltage goes negative? because it looks like a FWR. Thanks
Subject:
Electrical and Computer Engineering
Topic:
Electrical and Electronic Circuits
Posting ID:
13352
OTA ID:
104038
Rearrange formula (charging battery)
A battery is charged. The relationship between the charging current, i amperes and the time, t hours passed, is given by the formula: i = 3 e to the power of -0.36 t Show the formula for i can be rearranged to give the time t as t= 1 divided by 0.36 log e (3/i) Show all steps of working this out please!
Subject:
Electrical and Computer Engineering
Topic:
Electrical and Electronic Circuits
Posting ID:
13639
OTA ID:
103234
Basic Bipolar Junction Transmitter
In a common base configuration, the collector is connected to ground through a 5V source and a 2kOhm resistor. The emitter is driven with a constant-current source. Betaf=120. The collector-emitter voltage is Vce=2v. Determine ic, ib, and ie. Doing KVL around the CE loop, I get ib=1.25x10^-5Amps. However, the book gets .0154mA. I thought the constant current connected to the emitter was irrelavant because I was doing KVL on that loop? Am I wrong? Thanks.
Subject:
Electrical and Computer Engineering
Topic:
Electrical and Electronic Circuits
Posting ID:
13794
OTA ID:
103642
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