Use Impedance to Find Amplitude and Phase

Use impedances to predict the amplitude and phase of VR as a function of frequency VR(t) = ? {see attachment for circuit diagram}

Mesh Current

Referring to the attached diagram: Determine the mesh current ia in the circuit shown. My Answer: Mesh1=(-12V)+4V+(250+75=25)*ia+100(1a-1b)=0 Mesh2=(-12V)+4V+(100+100+200)ib+100*(ib-ia)=0 Solve for mesh 1: 2V+350*ia+100*ia-100ib=0 2V+45deg(ia)-100*ib=0 Solve for mesh 2: -4V+400*ib+100*ib-100*ia -4V+500*ib-100*ia Solve for ia: 2V+450*ia-100*ib=0 100ib=2V+450*ia ib=.02+4.5*ia -4+500*(.02+4.5*ia)-100*ia=0 -4V+10+2250*ia-100*ia=0 4+2150*ia=0 Final answer: ia=(-.00186) Also: Determine the mesh current ib in the circuit shown in diagram My Answer: Take ia=(-.00186) from the final answer for #8 above. Ib=2V+450*(-.00186)-100*ib=0 2+(-.837)-100*ib=0 -100*ib=1.163 F... click for more

Capacitor

A capacitor is used in the electronic flash unit of a camera. A small battery with a constant voltage of 6 V is used to charge the capacitor with a constant current of 10 microamperes. How long does it take to charge the capacitor when C = 10 microfarads? My Answer: V=6V i=10mA C=10microF Wc=1/2CV^2*(t) Wc=1/2(10^-5)6^2*(t) Wc=18*10^-5*(t) Wc=6V*.01A=.06J Wc=.06J=18*10^-5*(t) t=.06/(18*10^-5)=333.33 Final answer: 333.33 s

Angles - Check Work

Determine a when (6angle(120deg))*(-4 + j3 + 2*exp(j *15) ) = a + jb. Note: angles are in degrees. My Answer: 6(angle)120deg*(-4+j3+2e^j15)=a+jb 2e^j15=2*(cos15deg+jsin15deg) 6(angle)120deg*(-4+j3+1.93+j.5176) 6*(-2.07+j3.52)= 12.42+j21.12 Final answer: a=(-12.42) Determine b My Answer: B=21.12

Inductance - Check Answer

Find the value of the inductance L shown in the attached diagram. My Answer: V=L*d(i)/d(t) L=V/d(i)/d(t) V=25cos250t I=14sin250tmA d(i)=14cos250t L1=(25cos250t)/(14cos250t)=25/14=1.7857 Lt=2L+2L+L^2/2L= 2L+2L+1/2L=4.5L Lt=1.765*(2L+2L+L+L)= 1.765*6L=10.71 L=10.71/4.5=2.38 Final answer: 2.38