Mesh analysis of circuit

Using mesh analysis, find the voltage gain Av = V2/V1 in the circuit. See attached file for full problem description.

Superposition of current

Using superposition, determine the component of the current through R3 that is due to VS2. VS1 = VS2 = 450V. (see diagram in attached file)

Thevenin Equ. resistance

Find the Thevenin equivalent resistance seen by resistor R3 in the circuit. Compute the Thevenin (open-circuit) voltage and the Norton (short-circuit) current when R3 is the load. VS1=VS2= 450V (see diagram in attached file)

Efficiency and power of circuit

The equivalent circuit of Figure P3.57 has Vt = 35 V and Rt = 600 ohms. If the conditions for maximum power transfer exist, determine the value of RL, power of RL, and efficiency of the circuit. See diagram in attached file.

Electrical Grounding and polarity

To whom it may concern, From chemistry I understand that electron flow is from negative to positive, in the external circuit. I also understand that "conventional current" flows positive to negative, and is used to solve mathamatical electricity problems and it was determined back in the day as current direction. But, if the actual physical flow of current is from neg to pos why do we ground the negative terminal of DC circuits. Wouldn't the electrons go straight into the ground and not return to the positive terminal to complete the circuit. In a car for example the neg terminal is grounded. If DC flows in one direction how can it go from the positive terminal to ground/neg? Than... click for more