Utility and Indirect Utility Mathematical Proof

Consider the problems of maximizing u(x) subject to px = y and maximizing v(u(x)) subject to px = y, where v(u) is strictly increasing over the range of u.  Prove that x* solves the first problem if and only if it also solves the second problem.


This is what I got, however i dont think its entirely correct.

To solve the first problem: maximizing u(x) subject to px = y
Assuming x is a one variable commodity bundle,
Lagrangean equation: L = u(x) - b(px-y)
First order condition:
dL/dx = U'x - bp = 0
dL/db = px - y =0
from the second equation, x* = y/p

To solve the second problem: maximizing v(u(x)) subject to px = y
Assuming x is a one variable commodity bundle,
Lagrangean equation: L = v(u(x)) - b(px-y)
First order condition:
dL/dx = V'*U'x - bp = 0
dL/db = px - y =0
from the second equation, x* = y/p

obviously, these two problems yield the same solution x* = y/p.
therefore, if x* solves the first problem if and only if it also solves the second problem.

Now, assuming x is a multi-variable commodity bundle,
To solve the second problem: maximizing  u(x1, x2) subject to p1x1+p2x2 = y
Lagrangean equation: L = u(x1, x2) - b(px1+p2 -y)
First order condition:
dL/dX1 = U'x1 - bp1 = 0                           (1)
dL/dX2 = U'x2 - bp2 = 0                           (2)
dL/db = p1x1 +p2x2 - y =0                           (3)
from the first two equations, U'x1 / U'x2 = p1/p2   (4)

Now, we turn to the second problem: maximizing v(u(x)) subject to px = y
Assuming x is a one variable commodity bundle,
Lagrangean equation: L = v(u(x)) - b(px-y)
First order condition:
dL/dX1 = V'*U'x1 - bp1 = 0                          (5)
dL/dX2 = V'*U'x2 - bp2 = 0                           (6)
dL/db = p1x1 +p2x2 - y =0                           (7)
from the equations (5) and (6), U'x1 / U'x2 = p1/p2   (8)

then we find that equation system (7) and (8) are exactly the same as equation system (3) and (4), which means that these two problems yield the same solution set x*.
Therefore, if x* solves the first problem if and only if it also solves the second problem.

(End)



Looking further on the net, i found this:
http://econ.bu.edu/manove/EC701/MicroSlidesIndUtilPrint.pdf
(definition and proposition 3.51)  I think thats what my answer should look more like, but i dont know if that correctly answers the question.  My prof said its a very long proof found in a textbook (which i cant find)

Please help!