Automata and Computability
Show the error in the following fallacious “proof” that P NP. Proof by contradiction. Assume that P = NP. Then SAT P. So, of some k, SAT TIME(nk). Because every language in NP is polynomial time reducible to SAT, NP TIME(nk). Therefore P TIME(nk). But, by the time hierarchy theorem, TIME(nk+1) contains a language which isn’t in TIME(nk), which contradicts P TIME(nk). Therefore P NP.
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By OTA: Maddu Shankar, MSc
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