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Computer Science, Data Structures and Algorithms
Year 1

Automata and Computability


Show the error in the following fallacious “proof” that P  NP.  Proof by contradiction.  Assume that P = NP.  Then SAT  P.  So, of some k, SAT  TIME(nk).  Because every language in NP is polynomial time reducible to SAT, NP  TIME(nk).  Therefore P  TIME(nk).  But, by the time hierarchy theorem, TIME(nk+1) contains a language which isn’t in TIME(nk), which contradicts P  TIME(nk).  Therefore P  NP.

See attached file for full problem description.

Attachments
Problem A142.doc  View File

By OTA:  Maddu Shankar, MSc

OTA Rating:  4.6/5

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