Checkout
checkout
view
Your Cart Your Cart: item(s)
Subjects -> Chemistry -> Polymer Chemistry -> Posting #24738
Add to Shopping Cart
$2.19 Instant Download
Chemistry, Polymer Chemistry
Year 4

Entropy of mixing


I am trying to figure out how, for the entropy of mixing of two polymers, one gets from:

Change in entropy of mixing (delta S sub m) = k[(N1 + N2) ln (N1 + N2) - N1 ln N1 - N2 ln N2]

to the result:

change in entropy of mixing (delta S sub m) = -k(N1 ln v1 + N2 ln v2)  where v1 and v2 are the volume fractions of the two polymers 1 and 2 respectively.  What assumptions need to be made to go from the first equation to the second?  How algebraically does one make the rearrangements necessary?  Please be explicit.

Note that the first equation arises from Bolztmann's relationship:

delta S sub m (entropy of mixing)  k ln (Omega)  where omega is the number of possible arrangements in space that the molecules can assume.  Omega ends up being equal to (No/(N1!N2!))  and then Stirling's approximation is applied to get the first equation I indicated above.  

By OTA:  Yinon Shafrir, PhD

OTA Rating:  5/5

Your Price:  $2.19  (original value ~$23.94)

What's included:

  • Plain text response
  • Attachment(s):
    • BM 24738.pdf
    • BM 24738.doc
$2.19 Download Add to Cart

Add to Shopping Cart
$2.19 Instant Download

Page generated in 0.0114 seconds

About Us ·  Contact Us ·  Samples ·  Solutions ·  Legal Terms and Conditions ·  Privacy Policy

©2008 SolutionLibrary.com

Search for Solutions About Us Samples