pratical question - electro chemistry, redox reactions, and inorganic chemistry

4. A pratical application problem which I have recently encountered: Recently while a stainless steel reactor vessel was being polished, a problem occurred with the workers' environment. While monitoring atmospheric composition while working in the vessel, high levels of carbon monoxide (above 100 parts per million) were detected. The walls of the vessel were being electro-polished by use of dilute solutions of phosphoric and sulfuric acids being applied to the wall, and direct currents of electricity being conducted through the vessel, with the vessel itself functioning as the anode. Now, the question that was asked to me is what would account for the abnormally high levels of CO... click for more

General Electrochemistry Problems

Problems found in second year quantitative analysis course: 1. Answer the following questions based on the reaction... a) identify the oxident and write a balanced half-reaction. Please see attached for full question.

Amount of energy required to purify copper using electrolysis?

The purification of copper by electrolysis involves an anode of impure copper and a cathode of pure copper. During the electrolysis, copper (II) ions leave the anode slab and plate onto the cathode slab. The reaction at the anode is Cu(s) = Cu2+(aq) +2e- The reaction at the cathode is Cu2+(aq) + 2e- = Cu(s) Therefore, it would appear that these two reactions cancel out leaving an emf of zero. I don't understand how you can calculate the amount of energy required to purify copper being that the emf is zero. How much energy (in joules) is required to purify a given amount (i.e. 100g) of copper? Is heat produced? Why or why not? If so, how much (heat)?

Efficiency of electrolysis (in joules).

The amount of product produced by electrolysis is limited by Faraday's law. Therefore, as I understand it, the amount of product produced depends on the amps rather than on the volts (although the minimum voltage for a given reaction plus overvoltage must be met). For example, lets say you have a reaction that requires at least 0.3 Volts (0.3 volts includes the necessary overvoltage) to run. Instead of using 0.3 Volts you decide to double the voltage to 0.6 Volts. Volts X Amps = Watts, and Watts can be converted directly into Joules. Therefore, according to my calculations, it would require twice as much energy (IN JOULES!!!) to produce the SAME AMOUNT of product at 0.6 Volts than ... click for more

Kinetics Review

I do not understand kinetics at all! Please assist me with these and the attached kinetics questions. Thanks very much. 1)Calculate the mole fraction of methanol (CH OH) in a mixture of equal masses of methanol and water. 3 2)Calculate the molar concentration of chloride ions in a solution prepared by dissolving 454g of CaCl in water and diluting to 500mL. 2 3)At 25 degrees Celcius calcium chloride has a solubility of 60g/100g water, whereas at 100 degrees celcius, the solubility is considerably less. what does this indicate about the dissolutin of calcium chloride in water? *Please see attached for co... click for more